Physics 163

Unit 3: Motion in Two-Dimensions

Problem Set D

 

Problem 11:

A ball is thrown straight upward and returns to the thrower's hand after 3.5 s in the air. A second ball is thrown at an angle of 33.3 degrees with the horizontal. At what speed (in m/s) must the second ball be thrown so that it reaches the same height as the one thrown vertically?

 

 

 

 

 
Vertically Thrown Ball
Ball Thrown at Angle
Vertical
Horizontal
Vertical
y = ???

viy = ???

ttotal = 3.5 s

tup = 1.75 s

ay = -9.8 m/s/s

vfy = 0 m/s (@ t = 1.75 s)

Not

Important

to this

Problem

y = ???

viy = vi • sin()

ay = -9.8 m/s/s

vfy = 0 m/s (@ peak)

t = ???

 

 

A discussion of the formulae for projectile motion, of the trajectory characteristics and of the basic strategy for solving such problems is provided on the Set D Overview Page.

Detailed information about and discussion of the strategies for solving non-horizontally launched projectile problems is provided online at The Physics Classroom.

 

 

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